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Pasted as text by lavr ( 17 years ago )
SELECT
[Коды].[Название ОУ],
COUNT([Русский].[Ключ]) AS [Всего сдавали ЕГЭ]

FROM [Русский] INNER JOIN [Коды] ON [Русский].[Код ОУ]=[Коды].[Код ОУ]

GROUP BY [Коды].[Название ОУ]

 

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