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Pasted as C by Damian ( 12 years ago )
#include <stdio.h>
#include <conio.h>
 
 
/* Prints out a combination like {1, 2} */
void printc(int comb[], int k) 
{
 printf("{");
 int i;
 for (i = 0; i < k; ++i)
 printf("%d, ", comb[i] + 1);
 printf("\b\b}\n");
}

/*
next_comb(int comb[], int k, int n)
Generates the next combination of n elements as k after comb
 
 
comb => the previous combination ( use (0, 1, 2, ..., k) for first)
k => the size of the subsets to generate
n => the size of the original set
 
 
Returns: 1 if a valid combination was found
0, otherwise
*/
int next_comb(int comb[], int k, int n) 
{
 int i = k - 1;
 ++comb[i];
 while ((i >= 0) && (comb[i] >= n - k + 1 + i)) 
 {
  --i;
  ++comb[i];
 }
 
 if (comb[0] > n - k) /* Combination (n-k, n-k+1, ..., n) reached */
  return 0; /* No more combinations can be generated */

 /* comb now looks like (..., x, n, n, n, ..., n).
 Turn it into (..., x, x + 1, x + 2, ...) */
 for (i = i + 1; i < k; ++i)
  comb[i] = comb[i - 1] + 1;
  
 return 1;
}

int main(int argc, char *argv[]) {
 int n = 5; /* The size of the set; for {1, 2, 3, 4} it's 4 */
 int k = 3; /* The size of the subsets; for {1, 2}, {1, 3}, ... it's 2 */
 int comb[16]; /* comb[i] is the index of the i-th element in the
                       combination */
 /* Setup comb for the initial combination */
 int i;
 for (i = 0; i < k; ++i)
  comb[i] = i;
  
 /* Print the first combination */
 printc(comb, k);

 /* Generate and print all the other combinations */
 while (next_comb(comb, k, n)) // generate
  printc(comb, k);

 getch();
 return 0;
}

 

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